(x^2+2x-3)/(x+1)^2

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Solution for (x^2+2x-3)/(x+1)^2 equation:


D( x )

(x+1)^2 = 0

(x+1)^2 = 0

(x+1)^2 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

(x^2+2*x-3)/((x+1)^2) = 0

x^2+2*x-3 = 0

x^2+2*x-3 = 0

DELTA = 2^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-2)/(1*2) or x = (-16^(1/2)-2)/(1*2)

x = 1 or x = -3

(x+3)*(x-1) = 0

((x+3)*(x-1))/((x+1)^2) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x-1 )

x-1 = 0 // + 1

x = 1

x in { -3, 1 }

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